A 25.0g sample of magnesium at 22.0 C absorbs 356.3 J of heat. The temperature of the magnesium rises to 36.5 C. What is the specific heat of the magnesium?
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356.3J = 25g * c *
(36.5*C - 22*C)
c = 0.983J/g*C
(36.5*C - 22*C)
c = 0.983J/g*C
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Start with the mathematical relationship, then solve for c
q = mcΔT ..... were q is the quantity of heat, m is the mass, c is the specific heat capacity and ΔT is the temperature difference
c = q / (mΔT)
c = 356.3J / 25.0g / 14.5C
c = 0.983 J/gC ....... to three significant digits.
q = mcΔT ..... were q is the quantity of heat, m is the mass, c is the specific heat capacity and ΔT is the temperature difference
c = q / (mΔT)
c = 356.3J / 25.0g / 14.5C
c = 0.983 J/gC ....... to three significant digits.