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[From: ] [author: ] [Date: 13-02-03] [Hit: ]
What is the specific heat of the magnesium?-356.(36.c = 0.983J/g*C-Start with the mathematical relationship,q = mcΔT .......
A 25.0g sample of magnesium at 22.0 C absorbs 356.3 J of heat. The temperature of the magnesium rises to 36.5 C. What is the specific heat of the magnesium?

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356.3J = 25g * c *
(36.5*C - 22*C)
c = 0.983J/g*C

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Start with the mathematical relationship, then solve for c
q = mcΔT ..... were q is the quantity of heat, m is the mass, c is the specific heat capacity and ΔT is the temperature difference

c = q / (mΔT)
c = 356.3J / 25.0g / 14.5C
c = 0.983 J/gC ....... to three significant digits.
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