Cobalt-60 is a radioactive isotope used to treat cancers of the brain & other tissues. A gamma ray emitted by an atom of this isotop has an energy of 1.33 MeV (1 MeV=1 million volts (eV) (10^6); 1 eV=1.602 x 10^-19 J). What is the frequency (in Hz) & wavelength (in m) of this gamma ray?
~Thanks to whoever helps :)
~Thanks to whoever helps :)
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Energy = E = hv, where h = Planck's constant = 6.626 x 10^-34 J*s; v = frequency in s^-1
E(gamma ray) = 1.33 MeV[(1 x 10^6 eV)/(1 MeV)][(1.602 x 10^-19 J)/(1 eV)]
E = 2.13 x 10^-13 J
v = E/h = (2.13 x 10^-13 J)/(6.626 x 10^-34 J*s) = do the math
c = λ*v, where λ = wavelength in m and c = speed of light = 3.00 x 10^8 m/s.
λ = c/v = (3.00 x 10^8 m/s)/(your calculated value for frequency) = wavelength.
Hope this is helpful to you. JIL HIR
E(gamma ray) = 1.33 MeV[(1 x 10^6 eV)/(1 MeV)][(1.602 x 10^-19 J)/(1 eV)]
E = 2.13 x 10^-13 J
v = E/h = (2.13 x 10^-13 J)/(6.626 x 10^-34 J*s) = do the math
c = λ*v, where λ = wavelength in m and c = speed of light = 3.00 x 10^8 m/s.
λ = c/v = (3.00 x 10^8 m/s)/(your calculated value for frequency) = wavelength.
Hope this is helpful to you. JIL HIR