The pressure of a smaple of CH4 gas (6.022 g) in a 30.0L vessek at 402K is _____atm.

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Use the gas equation to solve for pressure
You must calculate moles of CH4
molar mass CH4 = 16.04 g/mol
6.022g CH4 = 6.022/16.04 = 0.3754 mol CH4
PV = nRT
P = ??
V = 30.0L
n = 0.375
R = 0.082057
T = 402
Substitute:
P * 30.0 = 0.375 * 0.082057*402
P = 12.38/ 30.0
P = 0.413 atm