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Find formulas with grams of elements

[From: ] [author: ] [Date: 12-12-23] [Hit: ]
2100 g Pb/mol) = 0.(27.5 g I) / (126.904473 g I/mol) = 0.(0.10859 mol Pb) / 0.......
1) 22.5g Pb, 27.5g I
2) 5.8g Pb, 14.2g I

Please? Thank you!

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1)
(22.5 g Pb) / (207.2100 g Pb/mol) = 0.10859 mol Pb
(27.5 g I) / (126.904473 g I/mol) = 0.21670 mol I

Divide by the smaller number of moles:
(0.10859 mol Pb) / 0.10859 mol = 1.00
(0.21670 mol I) / 0.10859 mol = 2.00
Round to the nearest whole numbers to find the empirical formula:
PbI2

2)
(5.8 g Pb) / (207.2100 g Pb/mol) = 0.02799 mol Pb
(14.2 g I) / (126.904473 g I/mol) = 0.11190 mol I

Divide by the smaller number of moles:
(0.02799 mol Pb) / 0.02799 mol = 1.00
(0.11190 mol I) / 0.02799 mol = 4.00
Round to the nearest whole numbers to find the empirical formula:
PbI4
1
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