and if the H+ concentration is l x l0-8 and pH = -log (H+), then the pH is 8
5. This concentration of .00001 mole per liter strong acid HI is l x l0-5 moles per liter which will provide the same concentration of H+ in water solution, so the pH will be the -log (H+) which is 5
6. This NaOH solution is l x l0-5 moles per liter NaOH which will deliver the same concentration of OH- in water solution as it ionizes about l00% in dilute solutions.
(H+)(OH-)_ = l x l0-14th so if the (OH) concentration is l x l0-5, then the H+) or (H3O+) concentration must be l x l0-9th moles per liter. The two concentrations multiply to l x l0-14th
7. If the pH = 2 then the (H+) or H3O+ ion concentration must = l x l0-2 moles per liter
and if the (H+)(OH-) always multiply to l x l0-14th then the conc OH- = l x l0=12.