What will be the molarity of a solution made by taking 140ml of 1.8M HBr and diluting it to 220ml of water?
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Hi Gregory!
The easiest way to do any type of dilution problem is to memorize the dilution equation which is M1V1 = M2V2 where M1 and V1 stands for the molarity and volume of the original solution and M2 and V2 stands for the molarity and volume of the new solution. Keep in mind that when using the dilution equation, you can use either mL or L for the volume but just remember that the units have to be consistent on both sides of the equation. This example gave volume in mL but I just want to let you know that it works fine with L also.
For your problem, the original volume and molarity is 140mL and 1.8M and the new volume is 220mL. Plug the known values into the equation and you will get: (140mL)(1.8M)=(220mL)(xM). X represents the new molarity of the solution after the dilution and that's what we're trying to solve for. X=(140mL)(1.8M)/(220mL)=1.145M or just 1.1M if you want significant figures . Thus, the molarity of the solution after the dilution is 1.1M.
Good luck on chem and I hope this helped :)
The easiest way to do any type of dilution problem is to memorize the dilution equation which is M1V1 = M2V2 where M1 and V1 stands for the molarity and volume of the original solution and M2 and V2 stands for the molarity and volume of the new solution. Keep in mind that when using the dilution equation, you can use either mL or L for the volume but just remember that the units have to be consistent on both sides of the equation. This example gave volume in mL but I just want to let you know that it works fine with L also.
For your problem, the original volume and molarity is 140mL and 1.8M and the new volume is 220mL. Plug the known values into the equation and you will get: (140mL)(1.8M)=(220mL)(xM). X represents the new molarity of the solution after the dilution and that's what we're trying to solve for. X=(140mL)(1.8M)/(220mL)=1.145M or just 1.1M if you want significant figures . Thus, the molarity of the solution after the dilution is 1.1M.
Good luck on chem and I hope this helped :)