This is the problem:
z^2-64, 2z+16, z
and it says find the LCD...would it be 2z^2+16 then? you combine whatever is biggest together right.
z^2-64, 2z+16, z
and it says find the LCD...would it be 2z^2+16 then? you combine whatever is biggest together right.
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The LCD = 1
The LCM = 2z(z-8)(z+8)
The LCM = 2z(z-8)(z+8)
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Okay a little work needs to be done here first.
Factor the first two expressions we get:
(z-8)(z+8) [difference of squares)
2(z+8)
z
Now to find the LCD, find what is the least needed for all three terms to be the same, well they all need a (z-8) a (z+8) a z and a 2 so your LCD is:
2z(z-8)(z+8)
Factor the first two expressions we get:
(z-8)(z+8) [difference of squares)
2(z+8)
z
Now to find the LCD, find what is the least needed for all three terms to be the same, well they all need a (z-8) a (z+8) a z and a 2 so your LCD is:
2z(z-8)(z+8)
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I think you mean the 'least common multiple !' ...there are no fractions in your presentation !
factor to find prime factors...
z^2 - 64 = (z + 8)(z - 8)
2z + 16 = 2(z + 8)
z = z
the LCM is: 2 * z * (z + 8) * (z - 8)
@ß
factor to find prime factors...
z^2 - 64 = (z + 8)(z - 8)
2z + 16 = 2(z + 8)
z = z
the LCM is: 2 * z * (z + 8) * (z - 8)
@ß
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The Lowest Common Multiple is 1.
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Lowest Common Denominator
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Lowest Common Denominator