The solubility of Ca(OH)2 at room temp is 0.153 grams per 100 mL of water.
Calculate the maximum pH one can obtain when Ca(OH)2 is dissolved in water.
Calculate the maximum pH one can obtain when Ca(OH)2 is dissolved in water.
-
Ca(OH)2 -------> Ca+2 + 2 OH-
calc. moles Ca(OH)2: 0.153 g/molec. wt. Ca(OH)2= ?moles Ca(OH)2
?moles (OH-)= 2 x ? moles Ca(OH)2
?moles( OH-)/0.1L= conc. of [OH-]
pOH= - log[OH-]
pH= 14 - pOH
calc. moles Ca(OH)2: 0.153 g/molec. wt. Ca(OH)2= ?moles Ca(OH)2
?moles (OH-)= 2 x ? moles Ca(OH)2
?moles( OH-)/0.1L= conc. of [OH-]
pOH= - log[OH-]
pH= 14 - pOH