How much energy is involved in turning 73.0 g of solid bromine at -23 Degrees Celsius into liquid bromine gas at 80 degrees Celsius ? Is the energy released or absorbed? ( melting/freezing point of bromine is -7 degrees Celsius and the boiling/condensing point is 59 degrees Celsius; Hf= 66.15 J/g and Hv= 184.29 J/g )
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Energy is being absorbed since it is being heated.
1)q=mCT
C=specific heat
q=73 x C x (-23 - -7)
2) q=mHf
=73x66.15
=4.83E3
3) q=mCT
=73 x C x (59 - -7)
4) q=mHv
=73 x 184.29
=1.35E4
5) q=mCT
=73 x C x (80-59)
Then add up all values calculated in parts 1-5 to get energy.
I am not chem-pro by any means but my class has done similar questions. They usually provide you with specific heat capacity though. So I don't know how you would find it without that information.
1)q=mCT
C=specific heat
q=73 x C x (-23 - -7)
2) q=mHf
=73x66.15
=4.83E3
3) q=mCT
=73 x C x (59 - -7)
4) q=mHv
=73 x 184.29
=1.35E4
5) q=mCT
=73 x C x (80-59)
Then add up all values calculated in parts 1-5 to get energy.
I am not chem-pro by any means but my class has done similar questions. They usually provide you with specific heat capacity though. So I don't know how you would find it without that information.