What is the maximum amount of P2O5 that can theoretically be made from 235g of P4 and excess oxygen

Consider a situation in which 235g of P4 are exposed to 272 g of O2

1. What is the maximum amount of P2O5 that can theoretically be made from 235g of P4 and excess oxygen

2.What is the maximum amount of P2O5 that can theoretically be made from 272 g of O2 and excess phosphorus

1)
235 g . . . . . . . . 538 g
P4 + 5O2 ---> 2P2O5
(123.9). . . . . . .(141.94) {g/mol conversion factors}
1.90 mol . . . . . 3.80 mol
. . |___1 to 2_____|
divide down from 235 to 1.90
ratio across to 3.80
multiply up to 538 g
2)
. . . . . 272 g. . . 482.6 g
P4 + 5O2 ---> 2P2O5
. . . . . (32.00). .(141.94) {g/mol conversion factors}
. . . . 8.50 mol. . 3.40 mol
. . . . . .|__2 to 5__|
to 3 s.f. that's 483 g of P2O5