How much heat is required to melt 77.5 g of ice at its melting point?
Express your answer numerically in kilojoules.
Express your answer numerically in kilojoules.
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The heat required to melt 1 g of ice is 333.5 J/g .
To melt 77.5 g ice, 333.5*77.5 J = 25 846 J = 25.846 kJ are required
OG
To melt 77.5 g ice, 333.5*77.5 J = 25 846 J = 25.846 kJ are required
OG