I was looking over practice exams for a test I have coming up and came across this problem but really have no idea how to do it. can someone please go through the solving process and explain how you got your answer? Thanks in advance! :)
Codeine is a narcotic pain reliever that forms a salt with HCl. What is the pH of 0.064 codeine hydrochloride? (pKb=5.80)
Codeine is a narcotic pain reliever that forms a salt with HCl. What is the pH of 0.064 codeine hydrochloride? (pKb=5.80)
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Codeine is a weak base. Codeine HCl is the salt of a weak base and so would create an acidic solution.
pKb of codeine equals 5.80. The pKa of codeine HCl = 8.20
The chemical reaction is this:
CodeineH+ + H2O <==> Codeine + H3O+
The Cl- is a spectator ion.
We need the Ka, which is 6.3 x 10^-9
6.3 x 10^-9 = [(x) (x)] / 0.064
x = 2.0 x 10^-5 M (this is the H3O+ concentration)
pH = 4.70
Here's another problem of the same type as yours:
http://www.chemteam.info/AcidBase/Calc-s…
pKb of codeine equals 5.80. The pKa of codeine HCl = 8.20
The chemical reaction is this:
CodeineH+ + H2O <==> Codeine + H3O+
The Cl- is a spectator ion.
We need the Ka, which is 6.3 x 10^-9
6.3 x 10^-9 = [(x) (x)] / 0.064
x = 2.0 x 10^-5 M (this is the H3O+ concentration)
pH = 4.70
Here's another problem of the same type as yours:
http://www.chemteam.info/AcidBase/Calc-s…