Whats the ph of a 0.25 mol/L solution of magnesium hydroxide
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Whats the ph of a 0.25 mol/L solution of magnesium hydroxide

[From: ] [author: ] [Date: 12-01-05] [Hit: ]
50 = 0.pH = 14 - pOH= 14 - 0.3010 = 13.699 = 13.70-Mg(OH)2 0.25m/l isMg+2 + 2OH- 2* 0.......
help please :(

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Mg(OH)2 = Mg2+ + 2OH-
Hence 0.25M solution of Mg(OH)2 contains 2 x 0.25 = 0.5M OH-
pOH = -log[OH-] = -log0.50 = 0.3010
pH = 14 - pOH = 14 - 0.3010 = 13.699 = 13.70

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Mg(OH)2 0.25m/l is Mg+2 + 2OH- 2* 0.25 or 0.50m/l OH-

pOH= -log[OH-] =0.3 pH = 14-pOH = 14-0.3 = 13.7
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