Boiling point chemistry question
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Boiling point chemistry question

[From: ] [author: ] [Date: 11-12-15] [Hit: ]
so 1.1 mole has mass of 222 / 1.014= 218.9 g / mole .........
A 222mg sample of eugenol was dissolved in 1g chloroform (Kb = 3.63 C/m), increasing the boiling point by 3.68C . What is the molar mass of eugenol?

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delta T = kb x m

m = delta T / kb = 3.68 / 3.63 = 1.014 moles of solute / kg of solvent

we have .222g / 1 g of solvent or 222g / 1000g of solvent

so 1.014 moles = 222 g ;

1 mole has mass of 222 / 1.014 = 218.9 g / mole ... molar mass of eugenol
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