Which one of the following equilibriums is least affected by a
change in the volume of the system?
A. 2 C (s) + O2 (g) " 2 CO (g)
B. H2 (g) + S (l) " H2S (g)
C. 2 NO2 (g) " N2O4 (g)
D. H2O (l) " H2O (g)
E. 2 NO (g) + Cl2 (g) " 2 NOCl (g)
I sort of understand that changing volume affects concentration of the reaction but, how are you supposed to know to what degree?
change in the volume of the system?
A. 2 C (s) + O2 (g) " 2 CO (g)
B. H2 (g) + S (l) " H2S (g)
C. 2 NO2 (g) " N2O4 (g)
D. H2O (l) " H2O (g)
E. 2 NO (g) + Cl2 (g) " 2 NOCl (g)
I sort of understand that changing volume affects concentration of the reaction but, how are you supposed to know to what degree?
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Volume is to do with the amount of pressure in the container. What you look at to find out whether the equation is affected by the change in volume is the number of moles on each side of the equation.
A. There is 2 moles of Carbon + 1 mole of Oxygen --> 2 moles of Carbon Monoxide
In order for there to NOT be a change in the equilibrium the moles on either side must be equal. In this case on the left side there is 3 moles of gas and on the right there is 2 moles of gas.
Therefore there will be a change in the equilibrium.
B. There is 1 mole of Hydrogen + 1 mole of Sulfur --> 1 mole of Hydrogen Sulfide
There is a change in the equilibrium because there is 2 moles on the left side and 1 mole on the right side.
C. There is 2 moles of NO2 --> 1 mole of N2O4
There is a change in the equilibrium because there is 2 moles on the left side and 1 mole on the right side.
D. There is 1 mole of Water --> 1 mole of Water
Because the number of moles on each side is equal, there will NOT be a change in equilibrium.
This is the one that is least affected by a change in the volume of the system.
E. There is 2 moles of NO + 1 mole of Cl2 --> 2 moles of NOCl
There is a change in the equilibrium because there is 3 moles of gas on the left side and 2 moles on the right side.
That is how I tell which ones would react. Then if there is a different number of moles each time, the equation with the closest gap ( eg. 2 moles on the left to 1 mole on the right ) will be least affected compared to a large gap ( eg. 6 moles on the left to 3 moles on the right )
A. There is 2 moles of Carbon + 1 mole of Oxygen --> 2 moles of Carbon Monoxide
In order for there to NOT be a change in the equilibrium the moles on either side must be equal. In this case on the left side there is 3 moles of gas and on the right there is 2 moles of gas.
Therefore there will be a change in the equilibrium.
B. There is 1 mole of Hydrogen + 1 mole of Sulfur --> 1 mole of Hydrogen Sulfide
There is a change in the equilibrium because there is 2 moles on the left side and 1 mole on the right side.
C. There is 2 moles of NO2 --> 1 mole of N2O4
There is a change in the equilibrium because there is 2 moles on the left side and 1 mole on the right side.
D. There is 1 mole of Water --> 1 mole of Water
Because the number of moles on each side is equal, there will NOT be a change in equilibrium.
This is the one that is least affected by a change in the volume of the system.
E. There is 2 moles of NO + 1 mole of Cl2 --> 2 moles of NOCl
There is a change in the equilibrium because there is 3 moles of gas on the left side and 2 moles on the right side.
That is how I tell which ones would react. Then if there is a different number of moles each time, the equation with the closest gap ( eg. 2 moles on the left to 1 mole on the right ) will be least affected compared to a large gap ( eg. 6 moles on the left to 3 moles on the right )
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The answer to this question is actually B which makes so sense to me so now I don't know what to think
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