How many moles pf CaCl2 are in 350mL of a .3 M solution of CaCl2? How many g of CaCl2 is this

Give an explanation of possible. Thanks!

1 litre or 1000 mL of 0.3 M solution of CaCl2 contains 0.3 moles of CaCl2.
So 1 mL of 0.3 M solution contains 0.3/1000 moles of CaCl2, and 350 mL contains 350 x 0.3/1000 moles = 0.105 moles of CaCl2.
Molar mass of CaCl2 is 110.98 g/mol so 0.105 mol = 0.105 mol x 110.98 g/mol = 11.6529 g.