When the electron in a hydrogen atom moves from n=6 to n=1, light with a wavelength of___nm is emitted

SO heres the deal I THOUGHT I knew how to do this its not hard. Because it goes from 6 to 1 its exothermic and emmits radiation {energy} so the equation should go somethin like this 2.18x10^-18/{6.626x10^-34}{3.00x10^8) and all that times {{1/1^2}-{1/6^2}} but i come up with the wrong answer

I'll calculate it and see what I get.

1 / lambda = (Rh / hc)(1/nf^2 - 1/ni^2)
1 / lambda = ((2.18 x 10^-18) / (6.63 x 10^-14)(3.00 x 10^8))(1/(1^2) - 1/(6^2))
1 / lambda = (1.10 x 10^7)(0.972)
1 / lambda = 1.07 x 10^7
lambda = 9.35 x 10^-8 m = 93.5 nm

410.13
i m not certain please check..............:)