the balanced chemical equation is S8+12O2=8SO3. there are 5.5 moles of sulfur and i figured out that 44 moles of sulfur oxide will be produced. i just don't understand how to find how much oxygen will be consumed.
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S8(s) + 12O2(g) = 8SO3(g)
Presumable you showed ? mol SO3 = 5.5 mole S8 x 8 moles SO3 / 1 mole S8 = 44 mole SO3
Now do the same for oxygen:
? mole O2 = 5.5 mole S8 x 12 mole O2 / 1 mole S8 = 66 mole O2
Or if you are thinking in terms of mass:
? g O2 = 5.5 mole S8 x 12 mole O2 / 1 mole S8 x 32 g O2/ mole O2 = 2100 g O2.
Presumable you showed ? mol SO3 = 5.5 mole S8 x 8 moles SO3 / 1 mole S8 = 44 mole SO3
Now do the same for oxygen:
? mole O2 = 5.5 mole S8 x 12 mole O2 / 1 mole S8 = 66 mole O2
Or if you are thinking in terms of mass:
? g O2 = 5.5 mole S8 x 12 mole O2 / 1 mole S8 x 32 g O2/ mole O2 = 2100 g O2.
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5.5 x 12= 66 moles of O2