Write the molecular and net ionic equations for the reaction that occurs when the two solutions are mixed.
CuSO4 + 2KOH --> Cu(OH)2 + K2SO4
i don't know what to do or how to start it just gives me that 50.0ml of 1.00M of CuSO4 and 50.0ml of 2.00M of KOH are mixed and a precipitate forms and the temp of the mixtures rises from 21.5C to 27.7C.
Please help and show how im really lost. Thank You!
CuSO4 + 2KOH --> Cu(OH)2 + K2SO4
i don't know what to do or how to start it just gives me that 50.0ml of 1.00M of CuSO4 and 50.0ml of 2.00M of KOH are mixed and a precipitate forms and the temp of the mixtures rises from 21.5C to 27.7C.
Please help and show how im really lost. Thank You!
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The equation you have written is considered the "molecular" equation since the chemicals are written as if they were molecules. You could add the state of the chemicals:
CuSO4(aq) + 2KOH(aq) --> Cu(OH)2(s) + K2SO4(aq)
where aq means aqueous (water) solution and (s) means a solid or precipitate. The next step would be to write the Complete Ionic equation by recognizing that ionic materials that are soluble in water will ionize, whereas precipitates will not.
Cu^2+ + SO4^2- + 2K^+ + 2 OH^- --> Cu(OH)2(s) + 2K^+ + SO4^2-
Now look for the EXACT same materials on both sides and cancel them out. These are called spectator ions.
Cu^2+ + 2 OH^- --> Cu(OH)2(s)
This is the net ionic equation. The concentration stuff and temperature data would be used for stoichiometry problems or thermodynamic problems.
CuSO4(aq) + 2KOH(aq) --> Cu(OH)2(s) + K2SO4(aq)
where aq means aqueous (water) solution and (s) means a solid or precipitate. The next step would be to write the Complete Ionic equation by recognizing that ionic materials that are soluble in water will ionize, whereas precipitates will not.
Cu^2+ + SO4^2- + 2K^+ + 2 OH^- --> Cu(OH)2(s) + 2K^+ + SO4^2-
Now look for the EXACT same materials on both sides and cancel them out. These are called spectator ions.
Cu^2+ + 2 OH^- --> Cu(OH)2(s)
This is the net ionic equation. The concentration stuff and temperature data would be used for stoichiometry problems or thermodynamic problems.