Neutralize??? so lost =[

If a portion of a tablet weighing 0.365 g neutralizes 2.30x10-4 moles of hydrochloric acid, how much acid would the whole tablet neutralize if it weights 1.84 g?

set up a proportion

0.365 1.84
------------= --------
2.30x10-4 x

solve for x

.365x = 1.84(.00023)
x = 0.001159
x = 1.159x10^-3

set up a proportion

1.84/0.365 = x/2.30x10-4 moles

http://www.kentchemistry.com/links/AcidB…

LOL

.365/(2.30*10^-4)*1.84 = answer in moles

you can find the exact number by copy and paste...; trust me its all there...