How many carbon dioxide molecules placed end-to-end would be needed to produce a length of 2.55 feet
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How many carbon dioxide molecules placed end-to-end would be needed to produce a length of 2.55 feet

[From: ] [author: ] [Date: 11-06-13] [Hit: ]
724 cm / ( 2.32 x 10^-8 cm ) = 3.how many times can 10-8cm fit in 2,55 feet?......
A carbon dioxide molecule is 2.32 Angstrom units long. How many molecules, placed end-to-end, would be needed to produce a length of 2.55 feet? (1 Angstrom = 10-8 cm.)

Please explain too to help me understand. 10 points to best answer!

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One CO2 molecule = 2.32 x 10^-8 cm
2.55 feet = 77.724 cm
77.724 cm / ( 2.32 x 10^-8 cm ) = 3.35 × 10^9 molecules of CO2

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1 molecule = 10-8cm
how many times can 10-8cm fit in 2,55 feet?
1
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