Molar heat of vap from fusion and vap
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Molar heat of vap from fusion and vap

[From: ] [author: ] [Date: 11-05-11] [Hit: ]
Hess Law says that no matter which pathway you take to get from point A to point B (in this case, from solid to gas) that the delta H (Hprod-Hrxt) will be the same.SO.Hsublimation = Hfusion + Hvaporization. 62.3 = 15.......
The molar heats of sublimation and fusion of iodine are 62.3kjmol and 15.3kjmol respectively calculate the molar heat of vaporization of liquid iodide?

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Sublimation is going directly from solid to gas. Hess' Law says that no matter which pathway you take to get from point A to point B (in this case, from solid to gas) that the delta H (Hprod-Hrxt) will be the same. SO.

H(solid to gas) = H(solid to liquid) + H(liquid to gas)

Hsublimation = Hfusion + Hvaporization. 62.3 = 15.3 + Hvap

THerefore Hvap = 62.3 - 15.3 = 47 kJ/mol

there should be little triangles (deltas) in front of all the H's listed above.

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