How to do this punnet square
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How to do this punnet square

[From: ] [author: ] [Date: 12-06-06] [Hit: ]
4. 25% of men will be normal.use Xh (h for haemophilia,1. Xh,2.......
A man who has hemophilia and a woman who is a carrier of the disorder have a daughter. What is the probability that their daughter has hemophilia? What is they have a son?

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Here there will be

1. 25% of women will get haemophilia.
2. 25% of women will be carriers.
3. 25% of men will get haemophilia.
4. 25% of men will be normal.

The phenotypic ratio will be 1:1:1:1

use Xh (h for haemophilia, and is a X linked and recessive hence small letter I used)

The four gametes formed are
1. Xh, Y for male
2. Xh, X for female

use these four gametes in punnet square, male gametes in a row and female gametes in a row.

Here I cannot draw the punnett square as yahooanswers do not have this facility.

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Man: AA (for disease)
Woman: aA (for carrier)

You do: A A
A
a
you get: AA, AA, aA, aA
They have a 50% of having a daughter with hemophilia

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Son or daughter doesn't matter unless one gender cant actually have the disorder. Its 3/4 because out of four options? Only one results in no disorder

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Son or daughter doesn't matter unless one gender cant actually have the disorder.

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http://www.hemophilia-information.com/he…
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