i had 10^8/ml and make a two-fold serial dilution of the culture so i had x2, x4, x6, x8, x16 and x32 dilution. how do i calculate the concentration of each dilution? please help moi.
thankyou :)
thankyou :)
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That is easy, you dilute it 2 times with every dilution, except for the x6 dilution, which does not belong in this series.
So first you had 1 x 10^8 per ml
in the 2x dilution, you have 0.5 x 10^8 per ml = 5 x 10^7 per ml
in the 4x dilution, you have 0.25 x 10^8 per ml = 2.5 x 10^7 per ml
in the x8 dilution, you have 0.125 x 10^8 per ml = 1.25 x 10^7 per ml
and so on....
So first you had 1 x 10^8 per ml
in the 2x dilution, you have 0.5 x 10^8 per ml = 5 x 10^7 per ml
in the 4x dilution, you have 0.25 x 10^8 per ml = 2.5 x 10^7 per ml
in the x8 dilution, you have 0.125 x 10^8 per ml = 1.25 x 10^7 per ml
and so on....