A tank is filled with water density =1000kg/m cubed up to height H2=1m. Above the water, there is a layer of oil with density =800kg/m cubed and thickness H1=4m. Outside pressure is Po=1atm:
Find the velocity of oil ejected from the first pipe at the depth H1:
Find the velocity of water ejected from the second pipe at depth H1+H2:
The area of the tank is very large in comparison with cross-sectional areas of the pipe.
The diagram can be found by clicking on the link:
http://www.facebook.com/photo.php?fbid=1…
Thank you!
Find the velocity of oil ejected from the first pipe at the depth H1:
Find the velocity of water ejected from the second pipe at depth H1+H2:
The area of the tank is very large in comparison with cross-sectional areas of the pipe.
The diagram can be found by clicking on the link:
http://www.facebook.com/photo.php?fbid=1…
Thank you!
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Hello
The fluids have such a velocity as if they had free fallen from height h accelerated by gravity.
so v = √(2gh) and is independent of the nature of the fluid (Theorem of Torricelli).
And the atmospheric pressure con be assumed to be equal at the top and the bottom and cancels out.
Velocity of the oil = √(2*9.81*4) = 8.86 m/s
Velocity of the water = √(2*9.81*5) = 9.9 m/s
Regards
The fluids have such a velocity as if they had free fallen from height h accelerated by gravity.
so v = √(2gh) and is independent of the nature of the fluid (Theorem of Torricelli).
And the atmospheric pressure con be assumed to be equal at the top and the bottom and cancels out.
Velocity of the oil = √(2*9.81*4) = 8.86 m/s
Velocity of the water = √(2*9.81*5) = 9.9 m/s
Regards
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its your homework dude wth.
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whats wrong with todays youth