Hardy-Weinberg problem

In a certain flock of sheep, 4 percent of the population has black wool and 96 percent has white wool. Assume that the population is in Hardy-Weinberg equilibrium.

1. If black wool is a recessive trait, what percentage of the population is heterozygous for this trait?

2. What percent of the population is homozygous for white wool?

Please help me on this problem. I don't know how to solve it
Thanks

I don't know either, but that doesn't stop me from trying.
Okay.
Check out the H-W second equation:

p^2 + 2pq + q^2 = 1
We'll let q be the allele frequency of the black wool allele (w), and p be the frequency of the white wool allele (W).

Now then, in that equation, the homozygous black wool sheep are represented by q^2.
So q^2 = 0.04
take the square root of both sides, and you have
q = 0.2
Cool.
Plug that into the first H-W equation
p + q = 1
and you find that
p = 0.8

Now you can do your problems.
1. If black wool is a recessive trait, what percentage of the population is heterozygous for this trait?
That's kind of an odd way of phrasing it, but the heterozygotes are represented by
2pq
in that equation we had above.
So 2 * 0.8 * 0.2 = 0.32 =
32% (answer)

2. What percent of the population is homozygous for white wool?
These guys are represented by
p^2
in that equation we had above.
So 0.8^2 = 0.64 =
64% (answer)

Check:
64% + 32% + 4% = 1
Also note that this fits our given, that 96% have white wool.