Let's say one of a virtual photon-photon pair escaped the black hole by Hawking's radiation. Since it's a virtual photon that escaped, can it be measured" or "felt" by an instrument outside of the horizon of a black hole?
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Yes. Once it gets away from its partner, it becomes a real photon.
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If photons have zero mass they would not be affected by the strong gravity of a Black hole'.
Black holes produce no magnetism .Therefore not electromagnetic field would be affected by a black hole. Hawking radiation is related to heat. However Heat is related to atomic interaction. The Black hole don't have an atomic structure consisting of bound neutrons,electrons and protons.
Since black Holes don't have a particular atomic architecture ,Atomic interaction could not take place inside the mass of a black hole.
Hence Black Holes if and where they exist would only be good to Just sit there with nothing else to do except to be invisible.
Black holes produce no magnetism .Therefore not electromagnetic field would be affected by a black hole. Hawking radiation is related to heat. However Heat is related to atomic interaction. The Black hole don't have an atomic structure consisting of bound neutrons,electrons and protons.
Since black Holes don't have a particular atomic architecture ,Atomic interaction could not take place inside the mass of a black hole.
Hence Black Holes if and where they exist would only be good to Just sit there with nothing else to do except to be invisible.