YES (if the mass remains the same)
lets say the sun hypothetically weighs 5 million grams and has a volume of 5 m^3, then it's density would be :
mass/volume = 5,000,000 / 5 = 1,000,000 gm^3
if it shrinks by 1,000,000:
mass/volume = 5,000,000 / 5x10^-6 = 1x10^12 gm^3
so it's density increased by 1,000,000
lets say the sun hypothetically weighs 5 million grams and has a volume of 5 m^3, then it's density would be :
mass/volume = 5,000,000 / 5 = 1,000,000 gm^3
if it shrinks by 1,000,000:
mass/volume = 5,000,000 / 5x10^-6 = 1x10^12 gm^3
so it's density increased by 1,000,000
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It depends on whether you're talking diameter or volume. With volume it's proportional, but with diameter the density increases inversely by the cube of the radius. So one millionth the diameter would be a million million million times the density, or 1 septillion. It would become a black hole. One millionth the volume would be the cube root of a millionth the diameter, or 1/100th, which is about 8,600 miles. That's about the size the sun will eventually become when it evolves into a white dwarf.
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1. If its volume shrinks to a millionth; its present density of 0.225 increases million fold to 225,000 (=225 kg/cubic centimetre) & its present radius of 700,000 km reduces to 7000 km (bigger than Earth's).
2. If you imply that the million times reduction pertains to the radius it is like this. Its radius (presently 700,000 km) reduces to 700 metres, implying the volume gets reduced by million million million th (10^-18). So the density gets multiplied by a factor of 10^18. Its present density of 0.225 increases to 225,000,000,000,000,000 g/cubic centimetre or 225 million tons every cubic centimetre. {I think it is far higher than that of any neutron star or white dwarf.}
2. If you imply that the million times reduction pertains to the radius it is like this. Its radius (presently 700,000 km) reduces to 700 metres, implying the volume gets reduced by million million million th (10^-18). So the density gets multiplied by a factor of 10^18. Its present density of 0.225 increases to 225,000,000,000,000,000 g/cubic centimetre or 225 million tons every cubic centimetre. {I think it is far higher than that of any neutron star or white dwarf.}
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it really isnt correct to say "shrinks 1 million times". This is not an accurate or even a rational statement.... is it shrinking a mile or an inch each of those times? your question would more properly be stated using the mass or the volume.
In general, as the suns size or area... the "volume" shrinks, then the density goes up. What you are really looking for is the "volume to density ratio of a sphere"
In general, as the suns size or area... the "volume" shrinks, then the density goes up. What you are really looking for is the "volume to density ratio of a sphere"
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Well if it shrinks that much in volume, then yes, the density
increase is in direct proportion.
If it shrinks that much in apparant diameter, then the density
increases as the cube of the decrease.
Try 1 million cubed, (10^27), on for size
increase is in direct proportion.
If it shrinks that much in apparant diameter, then the density
increases as the cube of the decrease.
Try 1 million cubed, (10^27), on for size
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I'm going to stab at four million times denser for some reason. idk though.