An object of 6.00 Kg at rest explodes in three parts m1= 2.00kg, m2=3.00kg m3= 1.00kg. After the explosion m1 will be moving north with a velocity of 3.00 m/s and m2 will be moving at 1.00 m/s, S of E. determine the velocity of m3
i need help resolving the answer
an explanation of your solution would be greatly appreciated
i need help resolving the answer
an explanation of your solution would be greatly appreciated
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The point here is that Momentum wil be conserved so that the momentum added of all three will be ZERO!!
-Therefore:
0 = m1v1 + m2v2 + m3v3
V3 = ( m1v1 + m2v2 )/ m3
V3 = 9 m/s
All the velocities have to cancel out!
The Vx of m2 is going in the negative direction and will cancel the velocity x of m3. Same way velocity y of m1 has to cancel with the velocities of m2 and m3 but since they are all different mass you ave to consider there momentum which factors in the differences in mass of the three masses.
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-Therefore:
0 = m1v1 + m2v2 + m3v3
V3 = ( m1v1 + m2v2 )/ m3
V3 = 9 m/s
All the velocities have to cancel out!
The Vx of m2 is going in the negative direction and will cancel the velocity x of m3. Same way velocity y of m1 has to cancel with the velocities of m2 and m3 but since they are all different mass you ave to consider there momentum which factors in the differences in mass of the three masses.
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find the momentum vectors. calculate the x and y components of each. then calculate the final x and y momentum vectors. find the resultant, then divide by mass to get velocity.