Physics question Help! quick!
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Physics question Help! quick!

[From: ] [author: ] [Date: 13-03-13] [Hit: ]
704) = 10.59 A.......
this is the first part:
An electric heater operating at full power draws a current of 14.2 A from a 152 V circuit.
What is the resistance of the heater?
Answer in units of Ω
and i got 10.70422535

i need help with this:
Assuming constant R, how much current should the heater draw in order to dissipate1200 W?
Answer in units of A

please show steps

-
Use Ohm's Law: R = V/I
R = 152/14.2 = 10.704...
You're correct for this one.

The equation for electrical power is P = I²R and you want the current I. Solve for I and you get I = √(P/R)
You know the power and you found resistance so plug those numbers in: I = √(1200/10.704) = 10.59 A.
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