this is the first part:
An electric heater operating at full power draws a current of 14.2 A from a 152 V circuit.
What is the resistance of the heater?
Answer in units of Ω
and i got 10.70422535
i need help with this:
Assuming constant R, how much current should the heater draw in order to dissipate1200 W?
Answer in units of A
please show steps
An electric heater operating at full power draws a current of 14.2 A from a 152 V circuit.
What is the resistance of the heater?
Answer in units of Ω
and i got 10.70422535
i need help with this:
Assuming constant R, how much current should the heater draw in order to dissipate1200 W?
Answer in units of A
please show steps
-
Use Ohm's Law: R = V/I
R = 152/14.2 = 10.704...
You're correct for this one.
The equation for electrical power is P = I²R and you want the current I. Solve for I and you get I = √(P/R)
You know the power and you found resistance so plug those numbers in: I = √(1200/10.704) = 10.59 A.
R = 152/14.2 = 10.704...
You're correct for this one.
The equation for electrical power is P = I²R and you want the current I. Solve for I and you get I = √(P/R)
You know the power and you found resistance so plug those numbers in: I = √(1200/10.704) = 10.59 A.