Susan do not answer this, you are of no help. Tuttores.com sucks

Someone please help! I need to know given the balanced chemical equation 2Fel2+3Cl2=2FeCl3+2l2, how many g of iron(111) chloride can be produced if 10.0 g of iron (11) iodide react with excess chlorine?

When an equation is balanced you have equal numbers of each type of atoms on each side.

2Fel2+3Cl2=2FeCl3+2l2

Fe, you have 2 on the left hand side and 2 on the right hand side, Fe is balanced.
I, you have 4 in the FeI2 on the left hand side and 4 on the right hand side in the 2I2, I is balanced.
Cl, you have 6 in the 3Cl2 on the left hand side and 6 in the 2FeCL3, chlorine is balanced.

So, the equation is balanced.

2 moles of FeI2 makes 2 moles of FeCl3

FeI2 has a molecular weight of 309.65 g/mole.

So, 10g of FeI2 is 0.03229 moles so you make the same number of FeCl3 or 0.03229 moles.

The molecular weight of FeCl3 is 162.20 g/mole so 0.03229 moles = 5.24 g

I will give you the way to answer any question of similar type, rather then simply give you the answer.

You have to start with a balanced equation. I will give you an example:

2 A + 3 B ----------> C + 2D

So what does the above equation mean? It means if you have 2 moles of A and 3 moles of B, you can get 1 mole of C and 2 moles of D. What happens if you have 4 moles of B? You still can only get 1 mole of C and 2 moles of D, as B is in excess.

You are told how many grams of Fe(II)I2 you have, so how many moles it that? And how does that relate to the number of moles of Fe(III)Cl3 you can get?

If your equation is indeed balanced, for each mole you get one mole of your desired compound.