A piece of iron with a mass of 35g is heated and then placed in a beaker containing 600. g of water. The tempe
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A piece of iron with a mass of 35g is heated and then placed in a beaker containing 600. g of water. The tempe

[From: ] [author: ] [Date: 13-03-13] [Hit: ]
The specific heat of iron is 0.451 J/gxC. What was the original temperature of the piece of iron.is heat gained or lost ?. i tried drawing an asked and given chart but i keep running into errors.......
Question: a piece of iron with a mass of 35g is heated and then placed in a beaker containing 600. g of water. The temperature of the water increase from 25 C to 33C. The specific heat of iron is 0.451 J/gxC. What was the original temperature of the piece of iron.

is heat gained or lost ?. i tried drawing an asked and given chart but i keep running into errors. i need help solving this problem! please

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We're solving for T initial.
Heat lost from metal = heat gained to water
Assuming no heat loss,
q(metal) = q(water)
q = mass x specific heat x delta T
The reason for (T - 33) is that after the metal cools and water heats,
both end up at the same final temperature.
(35g)(0.451 J/g C)(T - 33) = (600g)(4.184 J/g C)(33 - 25)
15.785T - 520.905 = 20083.2
15.785T = 20604.105
T initial iron= 1305 °C
1
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