The kernel of φ must be a subgroup of Z, but doesn't Z have several subgroups? Not sure where to begin
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Let φ: Z ---> Z12 be a group homomorphism.
Since Z is cyclic, φ is uniquely determined by φ(1), because φ(n) = n φ(1).
Since Z12 has 12 elements, there are 12 possibilities for φ(1); each of which yields a homomorphism.
I hope this helps!
Since Z is cyclic, φ is uniquely determined by φ(1), because φ(n) = n φ(1).
Since Z12 has 12 elements, there are 12 possibilities for φ(1); each of which yields a homomorphism.
I hope this helps!