On your first trip to Planet X you happen to take along a 250g mass, a 40-{\rm cm}-long spring, a meter stick, and a stopwatch. You're curious about the free-fall acceleration on Planet X, where ordinary tasks seem easier than on earth, but you can't find this information in your Visitor's Guide. One night you suspend the spring from the ceiling in your room and hang the mass from it. You find that the mass stretches the spring by 29.4cm . You then pull the mass down 11.0cm and release it. With the stopwatch you find that 11 oscillations take 16.3s
I have tried L=(mg)/k and gotten the answer 4.7. But it does not use half of the information given so I do not know if it is the correct equation.
I have tried L=(mg)/k and gotten the answer 4.7. But it does not use half of the information given so I do not know if it is the correct equation.
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d = 0.294 m
1) g = k*d/m
To find k: k = 4π²*m/T²
T = 16.3/11 = 1.4818 sec
So
k = 4.495 N/m
Using (1),
g = 4.495*0.294/0.25 = 5.286 m/s²
1) g = k*d/m
To find k: k = 4π²*m/T²
T = 16.3/11 = 1.4818 sec
So
k = 4.495 N/m
Using (1),
g = 4.495*0.294/0.25 = 5.286 m/s²
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what is 40-{\rm cm}- ?