Find the kinetic energy of a ton of water moving at 60 mi/h expressed as ft/lbf
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Find the kinetic energy of a ton of water moving at 60 mi/h expressed as ft/lbf

[From: ] [author: ] [Date: 12-09-28] [Hit: ]
pounds.So whats your issue.You work it the same way as you did in your answer but use Imperial units instead of kms SI units.So, for KE = 1/2 mV^2; you have m = W/g = 2000 lbs/32.2 ft/s^2 for the mass.......
kinetic energy = 1/2 (1000kg)(26.81 m/s)^2 = 359120 joules but ask me ft/lbf :S

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First, that's ft.lbf, not ft/lbf. Energy in Imperial units is given in foot.pounds.

So what's your issue. You work it the same way as you did in your answer but use Imperial units instead of kms SI units.

So, for KE = 1/2 mV^2; you have m = W/g = 2000 lbs/32.2 ft/s^2 for the mass. And V = 60 mph = 88 ft/sec for the speed. And there you are: KE = 1/2 * (2000/32.2) * 88^2 = ? ft.lbs. ANS You can do the arithmetic.
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