The car accelerates uniformly and reaches a speed Vb of 3.40 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 1.90 to 6.10 seconds.
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acceleration a = 3.4m/s / 8s = 0.425m/s^2
distance after 1.9s = 0.5*a*1.9^2 m = 0.767m
distance after 6.1s = 0.5*a*1.9^2 m = 7.907m
so distance travelled between 1.9 and 6.1s = 7.907 - 0.767m = 7.14 m
(a model car perhaps?)
distance after 1.9s = 0.5*a*1.9^2 m = 0.767m
distance after 6.1s = 0.5*a*1.9^2 m = 7.907m
so distance travelled between 1.9 and 6.1s = 7.907 - 0.767m = 7.14 m
(a model car perhaps?)