Finding energy release in alpha decay
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Finding energy release in alpha decay

[From: ] [author: ] [Date: 12-08-18] [Hit: ]
00179 u.the spaces above signify the chemical label in a sense.. ex. radon has 86 protons and 134 neutrons.-The energy released is the difference in mass between Rn-220 and Po-216+a.......
Find the energy released in the alpha decay of 220 86 Rn (220.01757 u). (Hint: 216 84 Po has a mass of 216.00179 u.)

the spaces above signify the "chemical label" in a sense.. ex. radon has 86 protons and 134 neutrons.

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The energy released is the difference in mass between Rn-220 and Po-216+a.
An alpha particle has a mass of 4.00151 u.
The difference is 220.01757u-(21.00179u+4.00151u)=195.0142…
One atomic mass unit is equal to 931.49406 MeV/c^2
The mass difference in MeV/c^2 is then 195.01427*931.49406=181.65463 GeV/c^2
The energy release is equal to the mass difference, so the energy released is 181.65463 GeV
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