Physics 2 applying Coulomb's Law with solution help please!! Thank you
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Physics 2 applying Coulomb's Law with solution help please!! Thank you

[From: ] [author: ] [Date: 12-06-30] [Hit: ]
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A 40 μc charge is positioned on the x-axis at x=4 cm. Where should a -60 μC charge be placed to produce a net electric field of zero at the origin?

The answer will be 5 cm

Thank you so much!

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Coulomb's Law gives the force between charges as

F = q1*q2/(4*π*ε0*r²)

The field from a point charge is E = q/(4*π*ε0*r²)

The fields from two charges along the line between them is the algebraic sum of the fields from each charge. The distance of the 40 µC charge is 4 cm, the distance of the -60 µC charge is x

E = 40/(4*π*ε0*4²) - 60/(4*π*ε0*x²)

you want E = 0 at this point x:

40/(4*π*ε0*4²) - 60/(4*π*ε0*x²) = 0

40/16 - 60/x² = 0

60/x² = 40/16

x = √[16/40 * 60] = 4.9 cm round to 1 sig fig to get 5 cm
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