Can you help me answer this Math Problem, Please?!
Favorites|Homepage
Subscriptions | sitemap
HOME > > Can you help me answer this Math Problem, Please?!

Can you help me answer this Math Problem, Please?!

[From: ] [author: ] [Date: 12-06-30] [Hit: ]
How much he invested at 5% and 7%?2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,......
1.) Mr. Ocampo invested P20,000, part of the amount at 5% annual interest, the remaining at 7% at the end of year, he earned P1,160. How much he invested at 5% and 7%?
=

2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,130 from his investments.
a.) how much did he invest at 10%?
b.) how much did he invest at 90%?

I'm begging you to answer this question so that i can pass my homework. Please?

-
1.) Total amount invested =20,000
Amount invested 5% annual interest = x
Invested at 7% = (20000−x )
Earning on amount x at 5%= x×5/100 =0.05x
Earning on amount (20000−x ) at 7%= (20000−x )×7/100 = 1400−0.07x
Total earning in the year =(1400−0.07x) +0.05x=1400−0.02x
Hence 1400−0.02x=1160
→x=12000
Amount invested 5% annual interest = x =12000
Invested at 7% = (20000−x ) =20000−12000 = 8000


2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,130 from his investments.
Total amount invested =12,000
Amount invested 10% annual interest = x
Invested at 9% = (12000−x )
Earning on amount x at 10%= x×10/100 =0.10x
Earning on amount (12000−x ) at 9%= (20000−x )×9/100 = 1080−0.09x
Total earning in the year =(1080−0.09x) +0.10x=1080+0.01x
Hence 1080+0.01x=1130
→x=5000
a.) how much did he invest at 10%
Amount invested 10% annual interest = x =5000

b.) how much did he invest at 9%?
Invested at 9% = (12000−x ) =12000−5000 = 7000

-
1) LET THE AMOUNT INVESTED AT 7% BE X P

THEN THE AMOUNT INVESTED AT 5% WILL BE ( 20,000 - X ) P

INTEREST EARNED IN 1 YEAR =

0.07X + 0.05 ( 20000 - X) = 1160

0.07X + 1000 - 0.05X = 1160

0.02X = 160

X = 160 /0.02 = 8000

ANSWER 8000P AT 7% AND 12000P AT 5%
CHECK
8000 x 7/100 = 560 P
12000 x 5/100 = 600 P

ADD = 1160 P

2) THE INTEREST RATE MUST BE 9% AND NOT 90%

LET THE AMOUNT INVESTED AT 10% BE X P

THEN THE AMOUNT INVESTED AT 9% WILL BE ( 12000 - X) P

INTEREST EARNED IN 1 YEAR =

0.1X + 0.09 ( 12000 - X) = 1130

0.1X + 1080 - 0.09X = 1130

0.01X = 50

X = 50 /0.01 = 5000 P

ANSWER 5000P AT 10% AND 7000P AT 9%

CHECK

5000 x 10/100 = 500 P

7000 x 9/100 = 630P

ADD = 1130 P
1
keywords: Can,Math,answer,this,you,Please,Problem,me,help,Can you help me answer this Math Problem, Please?!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .