1.) Mr. Ocampo invested P20,000, part of the amount at 5% annual interest, the remaining at 7% at the end of year, he earned P1,160. How much he invested at 5% and 7%?
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2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,130 from his investments.
a.) how much did he invest at 10%?
b.) how much did he invest at 90%?
I'm begging you to answer this question so that i can pass my homework. Please?
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2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,130 from his investments.
a.) how much did he invest at 10%?
b.) how much did he invest at 90%?
I'm begging you to answer this question so that i can pass my homework. Please?
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1.) Total amount invested =20,000
Amount invested 5% annual interest = x
Invested at 7% = (20000−x )
Earning on amount x at 5%= x×5/100 =0.05x
Earning on amount (20000−x ) at 7%= (20000−x )×7/100 = 1400−0.07x
Total earning in the year =(1400−0.07x) +0.05x=1400−0.02x
Hence 1400−0.02x=1160
→x=12000
Amount invested 5% annual interest = x =12000
Invested at 7% = (20000−x ) =20000−12000 = 8000
2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,130 from his investments.
Total amount invested =12,000
Amount invested 10% annual interest = x
Invested at 9% = (12000−x )
Earning on amount x at 10%= x×10/100 =0.10x
Earning on amount (12000−x ) at 9%= (20000−x )×9/100 = 1080−0.09x
Total earning in the year =(1080−0.09x) +0.10x=1080+0.01x
Hence 1080+0.01x=1130
→x=5000
a.) how much did he invest at 10%
Amount invested 10% annual interest = x =5000
b.) how much did he invest at 9%?
Invested at 9% = (12000−x ) =12000−5000 = 7000
Amount invested 5% annual interest = x
Invested at 7% = (20000−x )
Earning on amount x at 5%= x×5/100 =0.05x
Earning on amount (20000−x ) at 7%= (20000−x )×7/100 = 1400−0.07x
Total earning in the year =(1400−0.07x) +0.05x=1400−0.02x
Hence 1400−0.02x=1160
→x=12000
Amount invested 5% annual interest = x =12000
Invested at 7% = (20000−x ) =20000−12000 = 8000
2.) A business invests P12,000. A part of it at 10% annual interest and the rest at 90%. After one year he earned P1,130 from his investments.
Total amount invested =12,000
Amount invested 10% annual interest = x
Invested at 9% = (12000−x )
Earning on amount x at 10%= x×10/100 =0.10x
Earning on amount (12000−x ) at 9%= (20000−x )×9/100 = 1080−0.09x
Total earning in the year =(1080−0.09x) +0.10x=1080+0.01x
Hence 1080+0.01x=1130
→x=5000
a.) how much did he invest at 10%
Amount invested 10% annual interest = x =5000
b.) how much did he invest at 9%?
Invested at 9% = (12000−x ) =12000−5000 = 7000
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1) LET THE AMOUNT INVESTED AT 7% BE X P
THEN THE AMOUNT INVESTED AT 5% WILL BE ( 20,000 - X ) P
INTEREST EARNED IN 1 YEAR =
0.07X + 0.05 ( 20000 - X) = 1160
0.07X + 1000 - 0.05X = 1160
0.02X = 160
X = 160 /0.02 = 8000
ANSWER 8000P AT 7% AND 12000P AT 5%
CHECK
8000 x 7/100 = 560 P
12000 x 5/100 = 600 P
ADD = 1160 P
2) THE INTEREST RATE MUST BE 9% AND NOT 90%
LET THE AMOUNT INVESTED AT 10% BE X P
THEN THE AMOUNT INVESTED AT 9% WILL BE ( 12000 - X) P
INTEREST EARNED IN 1 YEAR =
0.1X + 0.09 ( 12000 - X) = 1130
0.1X + 1080 - 0.09X = 1130
0.01X = 50
X = 50 /0.01 = 5000 P
ANSWER 5000P AT 10% AND 7000P AT 9%
CHECK
5000 x 10/100 = 500 P
7000 x 9/100 = 630P
ADD = 1130 P
THEN THE AMOUNT INVESTED AT 5% WILL BE ( 20,000 - X ) P
INTEREST EARNED IN 1 YEAR =
0.07X + 0.05 ( 20000 - X) = 1160
0.07X + 1000 - 0.05X = 1160
0.02X = 160
X = 160 /0.02 = 8000
ANSWER 8000P AT 7% AND 12000P AT 5%
CHECK
8000 x 7/100 = 560 P
12000 x 5/100 = 600 P
ADD = 1160 P
2) THE INTEREST RATE MUST BE 9% AND NOT 90%
LET THE AMOUNT INVESTED AT 10% BE X P
THEN THE AMOUNT INVESTED AT 9% WILL BE ( 12000 - X) P
INTEREST EARNED IN 1 YEAR =
0.1X + 0.09 ( 12000 - X) = 1130
0.1X + 1080 - 0.09X = 1130
0.01X = 50
X = 50 /0.01 = 5000 P
ANSWER 5000P AT 10% AND 7000P AT 9%
CHECK
5000 x 10/100 = 500 P
7000 x 9/100 = 630P
ADD = 1130 P