I notice in various problems (x/n)-(y/z)
=(zx-ny)/(n)(z)
I never learned this in my algebra class. How does this come out equally?
=(zx-ny)/(n)(z)
I never learned this in my algebra class. How does this come out equally?
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Im sure youve learned it even thuogh you dont kknow it. Its basic algebra is al - we are adding two rational expressions by giving them both the same denoominator.
x/n - y/z
xz/nz - y/z
xz/nz - yn/nz
(xz- yn)/ nz
This is not some special identity you need to memorize.
x/n - y/z
xz/nz - y/z
xz/nz - yn/nz
(xz- yn)/ nz
This is not some special identity you need to memorize.
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It's called a common denominator, or combining fractions with different denominators.
Assuming n and z are nonzero,
x/n = xz/nz
y/z = yn/zn
zn = nz
x/n - y/z = (xz - yn)/zn
Assuming n and z are nonzero,
x/n = xz/nz
y/z = yn/zn
zn = nz
x/n - y/z = (xz - yn)/zn
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To solve this, you need to put everything under a common denominator, which in this case is "nz".
So you get:
(xz/zn) - ( ny/zn)=
xz-ny/zn=
So you get:
(xz/zn) - ( ny/zn)=
xz-ny/zn=