Calculating work, heat deltaU and deltaH.

Calculating work, heat deltaU and deltaH for the reversible isothermal (constant temperature) expansion of 2 moles of an ideal gas from 16 Litres to 95 litres at 0 degress celcius.

*i only know how to calculate work by using this formula pressure = moles x gas constant x temp /volume then rearranging it into pressure x volume (basically work) = moles x gas constant x temp.

even so i might be wrong. so feel free to correct me,, and what about heat, deltaU and deltaH?

this is expansion isothermal. it means there is a change of volume but the temperature is constant.


1. Work
Work is defined as:
W= integral (P*dV)
As you know that
P = n*R*T/V

So,

W= integral (n*R*T/V * dV)
W= n*R*T* ln (V1/V2)

I am sure you can calculate it by yourself, but you should make all of the parameters in international system unit. (Kelvin, m^3)

2. delta U

Because it is isothermal, there is no change of temperature, it means that deltaU is zero

3. You can use fisrt law of thermodynamics

Q= deltaU + W
Q= 0 +W
Q=W


I hope it helps you