A solid sphere of radius 12.0 cm and mass 10.0 kg starts from rest and rolls without slipping a distance of L = 9.0 m down a house roof that is inclined at 37o. What is the angular speed about its center as it leaves the house roof? Use units of "rad/s
I really need help. Can someone point me in the right direction?
I really need help. Can someone point me in the right direction?
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I = k*m*R² where k = 0.4 for a solid sphere
H = LsinΘ = 5.416 m
Vf = √[2gH/(1+k)] = 8.708 m/s
w = Vf/R = 8.708/0.12 = 72.56 rad/sec
H = LsinΘ = 5.416 m
Vf = √[2gH/(1+k)] = 8.708 m/s
w = Vf/R = 8.708/0.12 = 72.56 rad/sec