The escape speed of a particular planet with a radius of 7.500e+6 m is 14,500 m/s. What is the mass of the planet?
can someone please show me what you did to get to the correct answer and what my answer should be?! Thank you!
can someone please show me what you did to get to the correct answer and what my answer should be?! Thank you!
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When the KE = PE on the planet's surface, the speed V in KE = 1/2 mV^2 is the so-called escape velocity (speed). PE = mGM/R on the surface of the planet with mass M at radius R = 7.5E6 m.
Thus from 1/2 mV^2 = mGM/R we solve for M = V^2*R/(2G) = (14500^2)*7.5E6/(2*6.67E-11) = 1.18207E+25 = 1.18E25 kg. ANS.
Thus from 1/2 mV^2 = mGM/R we solve for M = V^2*R/(2G) = (14500^2)*7.5E6/(2*6.67E-11) = 1.18207E+25 = 1.18E25 kg. ANS.