Physics- Escape Speed
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Physics- Escape Speed

[From: ] [author: ] [Date: 12-06-25] [Hit: ]
67E-11) = 1.18207E+25 = 1.18E25 kg.ANS.......
The escape speed of a particular planet with a radius of 7.500e+6 m is 14,500 m/s. What is the mass of the planet?

can someone please show me what you did to get to the correct answer and what my answer should be?! Thank you!

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When the KE = PE on the planet's surface, the speed V in KE = 1/2 mV^2 is the so-called escape velocity (speed). PE = mGM/R on the surface of the planet with mass M at radius R = 7.5E6 m.

Thus from 1/2 mV^2 = mGM/R we solve for M = V^2*R/(2G) = (14500^2)*7.5E6/(2*6.67E-11) = 1.18207E+25 = 1.18E25 kg. ANS.
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