Please help with this physics pulley question!
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Please help with this physics pulley question!

[From: ] [author: ] [Date: 12-06-21] [Hit: ]
what is the mass of the pulley?=>2 = 1/2 x m x (0.=>1/2 x 2 x (v/r)^2 = (8-6) x 9.=>1/2 x 2 x (3/0.4)^2 = 2 x 9.=>h = 2.......
an 8 kg weight is attached to a 6kg weight over a pulley. the pulley is a uniform disk with a moment of inertia I= 2Kg m^2 and a radius R=.4m. the block starts from rest, and after the 8kg block has fallen a distance h, it is observed to be traveling at 3m/s.

what is the mass of the pulley?

-
By I = 1/2mr^2
=>2 = 1/2 x m x (0.4)^2
=>m = 25 kg
=>By the law of enerrgy conservation:-
=>PE(loss) in 8 kg mass = KE(gain) by pully + PE(gain) by 6 kg
=>Mgh = 1/2Iω^2 + mgh
=>1/2Iω^2 = (M-m)gh
=>1/2 x 2 x (v/r)^2 = (8-6) x 9.8 x h
=>1/2 x 2 x (3/0.4)^2 = 2 x 9.8 x h
=>h = 2.87 m
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