How do I turn 1/(s+1)^2 into a partial fraction? Need it in the form A/(s+1) +B/(s+1) or similar for Laplace transform. Thanks!
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It's already in partial fraction form, since s+1 is irreducible.
As for the inverse Laplace transform, note that
L^(-1) {1/s^2} = t.
Hence, a shifting theorem yields
L^(-1) {1/(s+1)^2 = te^(-t).
I hope this helps!
As for the inverse Laplace transform, note that
L^(-1) {1/s^2} = t.
Hence, a shifting theorem yields
L^(-1) {1/(s+1)^2 = te^(-t).
I hope this helps!