Partial fractions with perfect square as denominator
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Partial fractions with perfect square as denominator

[From: ] [author: ] [Date: 12-06-21] [Hit: ]
L^(-1) {1/(s+1)^2 = te^(-t).I hope this helps!......
How do I turn 1/(s+1)^2 into a partial fraction? Need it in the form A/(s+1) +B/(s+1) or similar for Laplace transform. Thanks!

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It's already in partial fraction form, since s+1 is irreducible.

As for the inverse Laplace transform, note that
L^(-1) {1/s^2} = t.

Hence, a shifting theorem yields
L^(-1) {1/(s+1)^2 = te^(-t).

I hope this helps!
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