An elevator is moving upward at 1.02 m/s when it experiences an acceleration 0.28 m/s2 downward, over a distance of 0.76 m. What will its final velocity be?
--still dont get it... please help
--still dont get it... please help
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Vf^2 = Vi^2 - 2(ad).
Vf^2 = 1.02^2 -2(0.28 x 0.76).
Vf = 0.784m/sec.
Vf^2 = 1.02^2 -2(0.28 x 0.76).
Vf = 0.784m/sec.