The weight of 350ml of a diatomic gas at 0degree C and 2atm pressure is 1g.The wt. of one atom is
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The weight of 350ml of a diatomic gas at 0degree C and 2atm pressure is 1g.The wt. of one atom is

[From: ] [author: ] [Date: 12-05-30] [Hit: ]
Mass of 1 molecule = 30/(6.1 molecule contains 2 atoms Therefore mass of 1 atom = 15/(6.......
answer is 16/N
where N os avagadro constant

can anyone tell me the method

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Calculate the volume of the gas at STP = 0°C and 1.0Atm .

volume = 375*2 = 750mL or 0.750L
Mass of 1 mol of diatomic gas = 22.4/0.750*1 = 30 g
Mass of 1 molecule = 30/(6.022*10^23) g
1 molecule contains 2 atoms
Therefore mass of 1 atom = 15/(6.022*10^23)g

I get 15/ Avagadro's number = not 16
1
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