Can you please solve it algebraically, without using the substitution method (I dont know how to use the substitution method)?? I dont understand how to find at all....heres the function:
y = 3secxtanx
Also the question asks to find the curves area above the x-axis from x = -pi/6 to x = pi/3
Please help...
y = 3secxtanx
Also the question asks to find the curves area above the x-axis from x = -pi/6 to x = pi/3
Please help...
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∫ 3sextanx
3∫secxtanx dx
3 secx + C
Derivative of secx is just secxtanx
Then evaluate using your x-values-- you should be able to handle that part ;)
3∫secxtanx dx
3 secx + C
Derivative of secx is just secxtanx
Then evaluate using your x-values-- you should be able to handle that part ;)