A particle has charge of 2uC 50 cm away there is a -10uC charge
What is the electric field in the midpoint of the two charges
What is the electric field in the midpoint of the two charges
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E= Q / (4piξo r^2)= 9e9 Q/r^2
Since the charges are equidistant from the point where we want to find the field and direction of the field is away from the positive charged due to each charge
The resultant field is 9e9*12e-6 / 0.25² = 1.728e+6 N / C
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Since the charges are equidistant from the point where we want to find the field and direction of the field is away from the positive charged due to each charge
The resultant field is 9e9*12e-6 / 0.25² = 1.728e+6 N / C
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