Can someone please explain to me why the pH of the water changed so much compared to the pH of my water when i added the same amount of moles and volume of NaOH??
pH of buffer was 7.23
pH of water was 12.29
pH of buffer was 7.23
pH of water was 12.29
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Buffers resist changes to their pH. When you added NaOH, the hydroxides in solution were "balanced out" by the weak acid of the buffer dissociating more and releasing more protons (H+) into solution. Thus, the pH remains relatively unchanged.
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Water is a neutral (pH 7) substance, and has no capacity to resist change in pH. Therefore when you added the Sodium Hydroxide the pH of the water changed to that of the NaOH.
The buffer was (presumably) at an acidic pH and at equilibrium (Acid + H2O <--> Ionised Acid + H30+) and this change was resisted as you added the NaOH (Acid + H2O + NaOH <---> Salt + H2O). This reduced the pH change, which is what a buffer solution is supposed to do.
The buffer was (presumably) at an acidic pH and at equilibrium (Acid + H2O <--> Ionised Acid + H30+) and this change was resisted as you added the NaOH (Acid + H2O + NaOH <---> Salt + H2O). This reduced the pH change, which is what a buffer solution is supposed to do.
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Water is a neutral (pH 7) substance, and has no capacity to resist change in pH. Therefore when you added the Sodium Hydroxide the pH of the water changed to that of the NaOH.
The buffer was (presumably) at an acidic pH and at equilibrium (Acid + H2O <--> Ionised Acid + H30+) and this change was resisted as you added the NaOH (Acid + H2O + NaOH <---> Salt + H2O). This reduced the pH change, which is what a buffer solution is supposed to do.
The buffer was (presumably) at an acidic pH and at equilibrium (Acid + H2O <--> Ionised Acid + H30+) and this change was resisted as you added the NaOH (Acid + H2O + NaOH <---> Salt + H2O). This reduced the pH change, which is what a buffer solution is supposed to do.
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just give me the 10 pts...idrc about the question.